Advanced Functions setting for rotary table

[ddefocy]

Hello,

Struggling a little with the proper setting in LaserCad for my mini rotary table I just added.
Here is the dilemma. I have added an additional stepper driver for the 2phase motor that came equipped
with the mini rotary table purchased from LightObject (Stepper driver M542) I have it wired and works
very nicely but the settings in LaserCad need some tweaking.

Rotate Engrave is enabled: X
Rotate axis con(um) ???
Step per Rotate (pulse) ???
Current Diameter (mm) just assuming that is the diameter of the object being engraved.

What about the stepper driver itself (M542) what should the pulse/rev be set at ?

I would be very grateful if some body could help me out here please.

Thanks in advance.
Dennis
Woodstock , CT

[Techgraphix]

There are roughly two kinds of rotary units:
the ones with a chuck IN which the object is placed and the ones with a roller ON which the object is laid.
With the first you always have to enter values for the circumference of the object.
With the second one the circumference of the object is not important but the circumference of the roller is..
So depending on what type of rotary you have to use this menu a bit different:

The microstep setting of the M542 can be set as you like, as long as the appropriate value can be entered in the menu (not too big or too small)

Example:
If your stepperdriver is set to 1/16 and the reduction of the motor to the roller (assuming you have the second type) is 1:5, your steppermotor has 200 steps/360 degrees, then the number of steps for one revolution of the roller is:
16 x 5 x 200 = 16.000 steps / rotation
If the roller has a diameter of 35mm the circumference is Pi x 35 = ~110mm
So for every step the circumfrence of the roller travels 110/16.000 = 0,006872.. mm or 6,872 micrometer

Kees

[ddefocy]

Kees,

Thank you for the quick response.
to answer the question of which type of rotary system:
Its a two roller type. (25.4mm) diameter rollers.
The stepper driver is set to 6400 pulses/rev
and the gear ratio is 1:1 the stepper motor and the two roller gears are identical number of cogs.
I'm not sure as to where the stepper driver is set to ? you referred to 1/16 in your reply.

There is also one additional question regarding vector lines in the image those seem to run using a different setting ?
Can you elaborate a little on that ?

Thank you in advance.
Dennis
Woodstock , CT

There are roughly two kinds of rotary units:
the ones with a chuck IN which the object is placed and the ones with a roller ON which the object is laid.
With the first you always have to enter values for the circumference of the object.
With the second one the circumference of the object is not important but the circumference of the roller is..
So depending on what type of rotary you have to use this menu a bit different:

The microstep setting of the M542 can be set as you like, as long as the appropriate value can be entered in the menu (not too big or too small)

Example:
If your stepperdriver is set to 1/16 and the reduction of the motor to the roller (assuming you have the second type) is 1:5, your steppermotor has 200 steps/360 degrees, then the number of steps for one revolution of the roller is:
16 x 5 x 200 = 16.000 steps / rotation
If the roller has a diameter of 35mm the circumference is Pi x 35 = ~110mm
So for every step the circumfrence of the roller travels 110/16.000 = 0,006872.. mm or 6,872 micrometer

Kees

[Techgraphix]

I 'm not sure what you mean by the vector-lines-settings.. I can't find that... (i'm using a AWC608 wit LaserCad 7.52)

The microstep setting of your drivers was just an example. choose as you like and check the switches on your driver. But remind that a higher microstepping-setting also needs a higher datarate... slowing down the overall performance at a certain level..

Kees

[ddefocy]

I must be missing something so obvious here.
I'm also using the 608 controller and Lasercad 7.09
Ok so here is what I have :
M542 2-phase stepper driver set to 6400 pulses/rev
The mini table with •Motor: 42HS03 1.8degrees/step
1:1 gear ratio roller diameter of 25.4mm

And now I'm looking for specific input data for the advanced settings (rotary engrave) in LaserCad.
Rotate Axis con (um) ?
Step per Rotate (pulse) ?
Current Diameter (mm) ok this one is easy I'm testing two objects 1 @ 25.4mm and 1 @ 63.5mm

Totally appreciate your assistance. Thank You.

Dennis

[Techgraphix]

In my example:
Rotate Axis Con = 6,872
Step per Rotate = 16000

The same sum for your settings:
Since you set your stepperdriver to 6400 pulses/rev (= 1/32 microstep) and your reduction = 1:1, your step per Rotate = 6400
The diameter of your roller is 25,4mm so its circumference is PI (=3,1415926) x 25,4mm = 79,79643mm
per step the circumference of the roll will travel 79.79643/6400= 0,012468mm which is roughly the same as 12,468 micrometer.
So the Rotate axis con = 12,468

When you set the driver to 1/64 microstep the value of step per rotate will be double and so the Rotate axis control will be half the size..

Comprende, amigo?

BTW, i don't use this advanced settings at all, as i solved most of the rotational-unit "problems" with a little piece of electronics...

Kees

[Tech_Marco]

Dennis

The simple way is to draw a box on the rotary then measure the actual size and let the LaseCad to do the calculation. It would be the same method what we used to find the "um" for the X and Y.

Marco